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Perl shift Function
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Perl shift function removes and returns the first element of an array, shortening the dimension of the array with 1. This function is similar with pop function, which takes off the rightmost element of the array and opposite to unshift/push function that inserts a list at the beginning/end of the array. In connection with unshift, pop and push, this function can be used to simulate queues and stacks in Perl. In this short free tutorial I’ll show you how you can use Perl shift function inside your Perl script. I’ll give you some snippet code examples to highlight some of the features of this function. To begin with, Perl shift function has two syntax forms:
The parenthesis can be omitted, but if you want your code more readable or avoid some precedence issues, you can use them. Anyway, I suggest you to use strict and warnings in your script, to avoid any possible typos or other issues. If the array used as argument is empty, this function will return the undef value.The second form has no argument and in this case the Perl shift function will be applied on some special arrays: - @_ if you use it inside the lexical scope of a subroutine
- @ARGV if you use it outside the body of a subroutine
Next, I’ll show you a simple example:#!/usr/bin/perl
use strict;
use warnings;
# initialize an array
my @colors = qw(blue gray yellow white);
my $color = shift(@colors);
print "Removed: $color, Remained: @colors\n";
# it displays Removed: blue, Remained: gray yellow white
The first element of the array will be removed.
| Using shift with a stack array |
We can treat a stack as an unbounded array of things. We can simply treat an array like a stack, by adding or removing elements at the beginning of the array. In order to remove the first element of the array, you guessed, we use the Perl shift function, and to add an element in front of the array we use the unshift function. The shift & unshift functions treat the "left hand side" of the array as the top of the stack. Please take a look at the following example:#!/usr/bin/perl
use strict;
use warnings;
# initialize an array
my @stack = qw(1 2 3 4 5 6 7);
# remove the first element
shift @stack;
print "@stack\n";
# stack is now (2 3 4 5 6 7)
# insert an element in front of the stack
unshift(@stack, 1);
print "@stack\n";
# stack is now (1 2 3 4 5 6 7)
Another way of modeling an array as a stack is to use push & pop functions, instead of unshift & shift.
| Using shift with a queue array |
Using the Perl shift function you can very easily manipulate an array as a queue. So, you can use either push & shift to manipulate the array as a forward queue (push to enqueue onto the end of the array and shift to dequeue from the front of the array) or unshift & pop to manipulate the array as a backward queue (unshift to enqueue in front of the array and pop to dequeue onto the end of the array). See the following example:#!/usr/bin/perl
use strict;
use warnings;
# initialize an array
my @queue = qw(one two three four);
# implement a forward queue array
push (@queue, "five");
shift @queue;
print "@queue\n";
# it displays: two three four five
| Emulate a circular list with shift |
You can very easily emulate a simple circular list using shift and push (or pop and unshift). Look at the following short snippet code:#!/usr/bin/perl
use strict;
use warnings;
my @circularList = ('a'.. 'f');
push(@circularList, shift(@circularList));
print "\@circularList = @circularList\n";
# it expects: @circularList = b c d e f a
The shift function will return and take off the leftmost element of the circular list, i.e. 'a', and the push function will append this element at the end of the circular list. The elements of the circular list will move from right to left.
| Using shift within a subroutine |
Now I’ll show you an example about how you can use the Perl shift function within a subroutine. We want to define and use a subroutine that returns the sum of two numbers. Here is the snippet code:#!/usr/bin/perl
use strict;
use warnings;
sub add {
return (shift() + shift());
}
print "5 \+ 7 \= ", add(5, 7), "\n";
#it displays 5 + 7 = 12;
Perl has a specific way of handling subroutine arguments which are stored in the special @_ array. You can access the calling arguments either by accessing the @_ special array or accessing them one by one using $_[0], $_[1] and so on. In our example, we use shift without parentheses that means we are using by default the @_ special array. The first shift will get and discard the first element of @_ and the second shift will get and discard the next element. The subroutine will return the sum of the two numbers.It’s a common practice to get all the parameters passed into a subroutine with Perl shift function. We can assign these parameters to local variables, as follows: #!/usr/bin/perl
use strict;
use warnings;
sub add {
my $a = shift;
my $b = shift;
$a+$b;
}
print "5 \+ 7 \= ", add(5, 7), "\n";
#it displays 5 + 7 = 12;
Please note that our add subroutine looks like returning nothing, which is not entirely true. If we omit the return function at the end of a subroutine, Perl will return the last evaluated expression, in our case $a+$b.We can rewrite the above subroutine for an indefinite number of arguments, as follows: #!/usr/bin/perl
use strict;
use warnings;
sub add {
my $sum = 0;
foreach (@_) {
$sum += shift;
}
return $sum;
}
print "Sum = ", add(5, 7, 9), "\n";
#it displays Sum = 21;
Please note the using of foreach statement against the @_ special array and the addition assignment operator ("+=") here.
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